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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

PhysicsMediumsingle choice

The internal energy of a gas is $U = 3 P V$ . It expands from $V_{0}$ to $3 V_{0}$ against a constant pressure $P_{0}$ . The heat absorbed is:

Answer:

Solution:

$Δ U = 3 P_{0} (3 V_{0}) - 3 P_{0} V_{0} = 6 P_{0} V_{0}$ . $W = P_{0} \times 2 V_{0} = 2 P_{0} V_{0}$ . $Q = 8 P_{0} V_{0}$ . B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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