A cube initially has volume 1000 c m 3 . α = 2 × 1 0 − 5 per °C, heating = 50°C. Find first-order volume increase in c m 3 .

Δ V = V ( 3 α ) Δ T = 1000 ( 6 × 1 0 − 5 ) ( 50 ) = 3 c m 3 .

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A cube initially has volume $1000 c m^{3} . α = 2 \times 1 0^{- 5}$ per °C, heating = 50°C. Find first-order volume increase in $c m^{3}$ .

Answer:

Solution:

$Δ V = V (3 α) Δ T = 1000 (6 \times 1 0^{- 5}) (50) = 3 c m^{3}$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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