One mole of an ideal gas at temperature T was cooled isochorically till the gas pressure fell from P to n P . Then, by an isobaric process, the gas was restored to the initial temperature. The net a

Question

One mole of an ideal gas at temperature T was cooled isochorically till the gas pressure fell from P to n P ​ . Then, by an isobaric process, the gas was restored to the initial temperature. The net amount of heat absorbed by the gas in the process is:

TestHub · Accepted Answer

Isochoric: T → n T ​ , Q 1 ​ = C v ​ ( n T ​ − T ) . Isobaric back to T : Q 2 ​ = C p ​ ( T − n T ​ ) . Net = ( C p ​ − C v ​ ) T ( 1 − n 1 ​ ) = RT ( 1 − n − 1 ) . C.

Physics - Heat & Thermo Question with Solution | TestHub

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