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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumnumerical

For $a = - 64 x + 32$ released from $x = 2.5$ , find the speed at the origin, in m/s.

Answer:

15.50

Solution:

Amplitude 2 m about $x = 0.5$ ; at $x = 0$ the displacement from the centre is 0.5 m. $v^{2} = 64 (4 - 0.25) = 240$ , $v = 15.5$ m/s.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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