Heat required to convert 1 g ice at 0 ∘ C to steam at 10 0 ∘ C is: steam latent heat = 536 cal g − 1 .

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PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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Heat required to convert 1 g ice at $0^{\circ} C$ to steam at $10 0^{\circ} C$ is: steam latent heat $= 536 cal g^{- 1}$ .

Answer:

Solution:

$Q = m L_{f} + m c_{w} (100) + m L_{v}$ .

$Q = 80 + 100 + 536 = 716 cal .$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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