The maximum radiation from two bodies is at 480 nm and 600 nm. Find the ratio T 2 T 1 of their temperatures.

λ m T = b , so T 2 T 1 = λ 1 λ 2 = 480 600 = 1.25 . D.

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PhysicsHeat & ThermoHeat TransferEasy2 min

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The maximum radiation from two bodies is at 480 nm and 600 nm. Find the ratio $\frac{T _{1}}{T _{2}}$ of their temperatures.

Answer:

Solution:

$λ_{m} T = b$ , so $\frac{T _{1}}{T _{2}} = \frac{λ _{2}}{λ _{1}} = \frac{600}{480} = 1.25$ . D.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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