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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesHard2 minQB

PhysicsHardmultiple choice

One mole of a monatomic gas goes round a cycle $A \to B \to C \to A$ , where $A \to B$ is a straight line through the origin of a $P$ - $V$ graph (with $V_{B} = 2 V_{A}$ ), $B \to C$ is isochoric and $C \to A$ is isobaric, and $T_{A} = T_{0}$ . Then:

Options:(select one or more)

Answer:

A, B, C, D

Solution:

Same working as for the standard triangle cycle: $T_{B} = 4 T_{0}$ , $W = \frac{1}{2} P_{A} V_{A} = 0.5 R T_{0}$ , $C_{A B} = 2 R$ , $Q_{in} = 6 R T_{0}$ and $η = \frac{0.5}{6} = 8.33%$ . All four are correct.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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