The temperature of a gas is − 7 8 ∘ C and the average translational kinetic energy of its molecules is K . The temperature at which the average translational kinetic energy of the molecules of the sam

Question

The temperature of a gas is − 7 8 ∘ C and the average translational kinetic energy of its molecules is K . The temperature at which the average translational kinetic energy of the molecules of the same gas becomes 2 K is :

TestHub · Accepted Answer

​ K . E = 2 nf 1 ​ RT ​ T i ​ = − 7 8 ∘ C → 273 + [ − 7 8 ∘ C ] = 195 K ​ K.E α T To double the K.E energy temp also become double ​ T f ​ = 390 K T f ​ = 11 7 ∘ C ​

Physics - Heat & Thermo Question with Solution | TestHub

Options:

Doubts & Discussion