In an ideal energy-budget model, 1 kg water at 10°C is divided. Heat released by one part freezing at 0°C takes the other to steam at 10 0 ∘ C . cw = 1 cal / ( g ∘ C ) , Lf = 80 , Lv = 540 cal / g . F

Question

In an ideal energy-budget model, 1 kg water at 10°C is divided. Heat released by one part freezing at 0°C takes the other to steam at 10 0 ∘ C . cw = 1 cal / ( g ∘ C ) , Lf = 80 , Lv = 540 cal / g . Find steam mass in g to two decimals. No claim of spontaneous heat flow is made.

TestHub · Accepted Answer

If y g becomes steam, freezing part releases 90 ( 1000 − y ) cal. Steam part needs 630 y cal. Thus 90000 = 720 y , y = 125 g ; frozen mass = 875 g . This is energy accounting, not an unaided cold-to-hot heat-transfer process.

Physics - Heat & Thermo Question with Solution | TestHub

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