In the PV diagram of figure, an ideal gas does 5 J of work when taken along the process ab and 4 J when taken along process bc. What is the change in internal energy of gas when it is taken along the

Question

In the PV diagram of figure, an ideal gas does 5 J of work when taken along the process ab and 4 J when taken along process bc. What is the change in internal energy of gas when it is taken along the straight path from a to c? Out of two curves in the graph one is an isothermal process and other is an adiabatic process.

TestHub · Accepted Answer

Curve ab is the isotherm, so Δ U ab ​ = 0 ; bc is the adiabat, so Δ U b c ​ = − W b c ​ = − 4 J . Δ U a c ​ = Δ U ab ​ + Δ U b c ​ = 0 − 4 = − 4 J (same endpoints a and c).

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