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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

A particle has $U = 4 - 12 x + 3 x^{2}$ J. It is released at $x = - 1$ . The maximum value of $x$ is:

Answer:

Solution:

$F = 12 - 6 x$ , equilibrium $x = 2$ . Amplitude = $3$ , so $x_{ma x} = 5$ m.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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