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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

A particle on the $x$ -axis has potential energy $U = 2 - 20 x + 5 x^{2}$ J. It is released at $x = - 3$ . The maximum value of $x$ will be ( $x$ in m):

Options:

Answer:

Solution:

$F = - d U / d x = 20 - 10 x$ , equilibrium at $x = 2$ . Amplitude = $2 - (- 3) = 5$ , so the maximum $x = 2 + 5 = 7$ m.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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