A substance has density 10 g / cm 3 at 0 ∘ C and 9.7 g / cm 3 at 10 0 ∘ C . Its linear expansion coefficient is:

Using ρ ≃ ρ 0 ( 1 − 3 α Δ T ) , 9.7 = 10 ( 1 − 300 α ) gives α = 1 0 − 4 ∘ C − 1 , A. Exact cubic geometry gives α = 100 3 97 10 − 1 ≃ 1.02048 × 1 0 − 4 ∘ C − 1 .

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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A substance has density $10 g / cm^{3}$ at $0^{\circ} C$ and $9.7 g / cm^{3}$ at $10 0^{\circ} C$ . Its linear expansion coefficient is:

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Answer:

Solution:

Using $ρ ≃ ρ_{0} (1 - 3 α Δ T), 9.7 = 10 (1 - 300 α)$ gives $α = 1 0^{- 4}^{\circ} C^{- 1}$ , A. Exact cubic geometry gives $α =$ $\frac{3 \frac{10}{97} - 1}{100} ≃ 1.02048 \times 1 0^{- 4}^{\circ} C^{- 1}$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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