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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

Two particles in SHM have the same mean position, amplitude $A$ and period $T$ . At $t = 0$ one is at $+ A$ and the other is at $A / 2$ on the negative side, moving towards the mean position. Find the time when they first cross, in terms of $T$ .

Options:

Answer:

Solution:

$x_{2} = A cos (ω t - 3 π /4)$ . $cos ω t = cos (ω t - 3 π /4)$ at $ω t = 3 π /8$ , $t = \frac{3 T}{16}$ .

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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