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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

The acceleration of a simple harmonic oscillator is $a = - (35.28 m/s^{2}) cos 4.2 t$ . The amplitude is:

Answer:

Solution:

$a_{ma x} = ω^{2} A$ , so $A = 35.28/ 4.2^{2} = 35.28/17.64 = 2.0$ m.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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