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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

Find the period ratio $T_{ro d} / T_{s im pl e}$ for a thin uniform rod of length $L$ pivoted at a point $L /4$ from its centre and a simple pendulum of length $L$ .

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Answer:

Solution:

$I = \frac{M L ^{2}}{12} + M \frac{L ^{2}}{16} = \frac{7 M L ^{2}}{48}$ , $d = L /4$ , $l_{e q} = \frac{7 L}{12}$ . Ratio = $7/12$ .

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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