If one mole of a monoatomic gas ( γ = 3 5 ) is mixed with one mole of a triatomic gas ( γ = 3 4 ), the value of γ for the mixture is:

C v = 2 2 3 R + 3 R = 4 9 R , C p = 4 13 R . γ = 9 13 = 1.44 . B.

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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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If one mole of a monoatomic gas ( $γ = \frac{5}{3}$ ) is mixed with one mole of a triatomic gas ( $γ = \frac{4}{3}$ ), the value of $γ$ for the mixture is:

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Answer:

Solution:

$C_{v} = \frac{\frac{3}{2} R + 3 R}{2} = \frac{9}{4} R$ , $C_{p} = \frac{13}{4} R$ . $γ = \frac{13}{9} = 1.44$ . B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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