An isotropic solid has density 8.00 g / cm 3 at 0 ∘ C and 7.88 g / cm 3 at 10 0 ∘ C . Using the first-order density model, find α in units of 1 0 − 5 K − 1 . Give one decimal.

7.88 = 8 ( 1 − 300 α ) gives α = 300 0.015 = 5 × 1 0 − 5 K − 1 . Requested number = 5.0 .

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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An isotropic solid has density $8.00 g / cm^{3}$ at $0^{\circ} C$ and $7.88 g / cm^{3}$ at $10 0^{\circ} C$ . Using the first-order density model, find $α$ in units of $1 0^{- 5} K^{- 1}$ . Give one decimal.

Answer:

5.00

Solution:

$7.88 = 8 (1 - 300 α)$ gives $α = \frac{0.015}{300} = 5 \times 1 0^{- 5} K^{- 1}$ . Requested number $= 5.0$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

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