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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKinetic Theory of Gases and Gas LawsHard2 minQB

PhysicsHardnumerical

A vessel of volume 16.6 litres holds a mixture of hydrogen ( $M_{1} = 2$ g/mol) and helium ( $M_{2} = 4$ g/mol) at 300 K and $1 0^{5}$ Pa. The mixture has mass 2.0 g. Find the ratio of the mass of hydrogen to the mass of helium (two decimals). $R = 8.314$ J/(mol K).

Answer:

0.49

Solution:

Mean molar mass $a = \frac{m RT}{p V} = \frac{2.0 \times 1 0 ^{- 3} \times 8.314 \times 300}{1 0 ^{5} \times 0.0166} \times 1 0^{3} = 3.01$ g/mol. Then $\frac{m _{1}}{m _{2}} = \frac{1 - \frac{a}{M _{2}}}{\frac{a}{M _{1}} - 1} = \frac{0.249}{0.503} = 0.49$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Kinetic Theory of Gases and Gas Laws

⏱ 2mℹ️ Source: QB

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