A cylindrical rod with one end in a steam chamber and the other end in ice results in melting of 0.1 g of ice per second. If the rod is replaced by another rod with half the length and double the radi

Question

A cylindrical rod with one end in a steam chamber and the other end in ice results in melting of 0.1 g of ice per second. If the rod is replaced by another rod with half the length and double the radius of the first, and the thermal conductivity of the material of the second rod is 0.25 times that of the first, the rate at which ice melts in g $s^{- 1}$ will be:

Options:

Answer:

B

Solution:

The rate $\propto \frac{k r ^{2}}{l}$ . The factor is $0.25 \times 4 \times 2 = 2$ . The new rate is $0.2$ g $s^{- 1}$ . B.

TestHub · Accepted Answer

The rate ∝ l k r 2 ​ . The factor is 0.25 × 4 × 2 = 2 . The new rate is 0.2 g s − 1 . B.

Physics - Heat & Thermo Question with Solution | TestHub

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