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PhysicsHeat & ThermoDifferent processesMedium2 minPYQ_2020
PhysicsMediumnumerical

The change in the magnitude of the volume of an ideal gas when a small additional pressurePis applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantityTat constant pressure. The initial temperature and pressure of the gas were300 K and2 atmrespectively. If|ΔT|=C|ΔP|then value ofCin(K/atm)is __________

Answer:
150.00
Solution:

PV=nRT

PΔV+VΔP=0

ΔV=-ΔPPV  ....(i)

  In second case

PΔV=-nRΔT

ΔV=-nRΔTP    ...(ii)

equating (i) and (ii)

nRΔTP=-ΔPPV

ΔT=ΔP VnR

c=vnR

Putting the value of V, n and  R , C = 150 

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes
2mℹ️ Source: PYQ_2020

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