If a mixture of 28 g of Nitrogen, 4 g of Hydrogen and 8 gm of Helium is contained in a vessel at temperature 400 K and pressure 8.3 × 1 0 5 Pa , the density of the mixture will be :

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Total moles = 28 28 ​ + 2 4 ​ + 4 8 ​ = 5. V = P n RT ​ = 8.3 × 1 0 5 5 × 8.3 × 400 ​ = 0.02 m 3 = 20 litre. Total mass = 40 g ⇒ density = 20 40 ​ = 2 g / litre.

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