The coefficient of linear expansion of a 1.0 m rod varies linearly along its length from 2 × 1 0 − 5 ∘ C − 1 at one end to 4 × 1 0 − 5 ∘ C − 1 at the other. Its increase in length for a 10 0 ∘ C rise is:

α eff = ( 2 + 4 ) × 1 0 − 5 /2 = 3 × 1 0 − 5 ; Δ L = 3 × 1 0 − 5 × 1.0 × 100 = 3.0 × 1 0 − 3 m = 3.0 mm . Answer (B).

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PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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The coefficient of linear expansion of a 1.0 m rod varies linearly along its length from $2 \times$ $1 0^{- 5}^{\circ} C^{- 1}$ at one end to $4 \times 1 0^{- 5}^{\circ} C^{- 1}$ at the other. Its increase in length for a $10 0^{\circ} C$ rise is:

Options:

Answer:

Solution:

$α_{eff} = (2 + 4) \times 1 0^{- 5} /2 = 3 \times 1 0^{- 5}; Δ L = 3 \times 1 0^{- 5} \times 1.0 \times 100 = 3.0 \times 1 0^{- 3} m = 3.0 mm$ . Answer (B).

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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