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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesEasy2 minQB

PhysicsEasynumerical

A monoatomic gas at 400 K ( $γ = 1.67$ ) is expanded adiabatically to three times its volume. Find the final temperature in kelvin (one decimal).

Answer:

191.60

Solution:

$T_{2} = T_{1} (\frac{V _{1}}{V _{2}})^{γ - 1} = 400 \times 3^{- 0.67} = 191.6$ K.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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