Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

PhysicsMediumsingle choice

In the isothermal expansion of 10 g of gas from volume V to 2V the work done by the gas is 575 J. What is the root mean square speed of the molecules of the gas at that temperature?

Options:

Answer:

Solution:

$W = n RT ln 2 = \frac{m}{M} RT ln 2 \Rightarrow \frac{RT}{M} = \frac{W}{m l n 2} . v_{r m s} = \frac{3 RT}{M} = \frac{3 W}{m l n 2} = \frac{3 \times 575}{0.01 \times 0.693} \approx$ 499 m/s.

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...