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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

PhysicsMediumnumerical

A gas of rigid diatomic molecules at 300 K is compressed adiabatically to one-fourth of its volume. Find the mean rotational kinetic energy of a molecule in the final state, in units of $1 0^{- 21}$ J (two decimals, $k = 1.381 \times 1 0^{- 23}$ J $K^{- 1}$ ).

Answer:

7.21

Solution:

$T = 300 \times 4^{0.4} = 522.3$ K. A rigid diatomic molecule has 2 rotational degrees of freedom, so $E = k T = 1.381 \times 1 0^{- 23} \times 522.3 = 7.21 \times 1 0^{- 21}$ J.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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