An amount Q of heat is added to a monoatomic ideal gas, and the gas does a work 3 Q . The molar heat capacity in this process is:

Δ U = 3 2 Q = n 2 3 R Δ T , so n Δ T = 9 R 4 Q . C = n Δ T Q = 4 9 R . A.

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An amount $Q$ of heat is added to a monoatomic ideal gas, and the gas does a work $\frac{Q}{3}$ . The molar heat capacity in this process is:

Answer:

Solution:

$Δ U = \frac{2 Q}{3} = n \frac{3}{2} R Δ T$ , so $n Δ T = \frac{4 Q}{9 R}$ . $C = \frac{Q}{n Δ T} = \frac{9 R}{4}$ . A.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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