A paddle wheel in a thermally insulated tank holding 2 kg of water is turned by falling weights, doing 8.4 kJ of work on the water. Taking c = 4200 J k g − 1 K − 1 , find the rise in temperature of th

Question

A paddle wheel in a thermally insulated tank holding 2 kg of water is turned by falling weights, doing 8.4 kJ of work on the water. Taking $c = 4200$ J $k g^{- 1}$ $K^{- 1}$ , find the rise in temperature of the water in kelvin (one decimal). No heat enters the tank.

Answer:

1

Solution:

$Q = 0$ , so the work done on the water becomes internal energy: $W = m c Δ T$ . $Δ T = \frac{8400}{2 \times 4200} = 1.0$ K.

TestHub · Accepted Answer

Q = 0 , so the work done on the water becomes internal energy: W = m c Δ T . Δ T = 2 × 4200 8400 ​ = 1.0 K.

Physics - Heat & Thermo Question with Solution | TestHub

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