Physics - NLM Question with Solution | TestHub

$$2\mathrm{T}=5\mathrm{g}$$

$$\begin{array}{rlrl}& 4\mathrm{T}=10\mathrm{g}& \mathrm{T}=\frac{2{\mathrm{m}}_1{\mathrm{m}}_2\mathrm{g}}{{\mathrm{m}}_1+{\mathrm{m}}_2}=2.5\mathrm{g}& \Rightarrow \frac{{\mathrm{m}}_1{\mathrm{m}}_2}{{\mathrm{m}}_1+{\mathrm{m}}_2}=\frac{5}{4}\mathrm{kg}\end{array}$$

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[0pt] (XI-J)]

$$mg-N\cos \theta =ma\sin \theta$$