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Physics - NLM Question with Solution | TestHub

PhysicsNLMChallenging application of NLMMedium2 minQB

PhysicsMediuminteger

At time t seconds a particle of mass 3 kg has position vector r = 3t i - 4cos(t) j (in meters). The magnitude of the impulse of the force during the time interval $0 <= t <= pi /2$ (in $N - s$ ) is

Answer:

Solution:

$r = 3 t \hat{i} - 4 cos t \hat{j}$

$v = \frac{d r}{d t} = 3 \hat{i} + 4 sin t \hat{j}$

$v (0) = 3 \hat{i}$ and $v (π /2) = 3 \hat{i} + 4 \hat{j}$

Impulse $= m Δ v = 3 \times (4 \hat{j}) = 12 \hat{j}$ N-s

Magnitude of impulse $= 12$ N-s

Subject:PhysicsTopic:NLMSubtopic:Challenging application of NLM

⏱ 2mℹ️ Source: QB

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