A perfect gas is found to obey the relation P V 3/2 = constant, during an adiabatic process. If such a gas, initially at a temperature T , is compressed adiabatically to half its initial volume, then

Question

A perfect gas is found to obey the relation $P V^{3/2} =$ constant, during an adiabatic process. If such a gas, initially at a temperature $T$ , is compressed adiabatically to half its initial volume, then its final temperature will be

Options:

Answer:

C

Solution:

$T V^{γ - 1} =$ const with $γ = \frac{3}{2} : T_{f} = T (\frac{V}{V /2})^{1/2} = 2 T$ .

TestHub · Accepted Answer

T V γ − 1 = const with γ = 2 3 ​ : T f ​ = T ( V /2 V ​ ) 1/2 = 2 ​ T .

Physics - Heat & Thermo Question with Solution | TestHub

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