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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

PhysicsMediummultiple choice

A fixed quantity of an ideal gas can be expanded from an initial state to a certain volume through two different processes (i) $P V^{2} =$ constant and (ii) $P = K V^{2}$ where $K$ is a constant. Then

Options:(select one or more)

Answer:

B, D

Solution:

(i) $P V^{2} =$ const $\Rightarrow T V =$ const: $T$ falls on expansion. (ii) $P = K V^{2} \Rightarrow T \propto V^{3} : T$ rises. Final temperature is greater in (ii) (B true). $C_{1} = C_{V} + \frac{R}{1 - 2} = C_{V} - R < 0$ (heat rejected on expansion); $C_{2} = C_{V} + \frac{R}{1 - ( - 2 )} = C_{V} + \frac{R}{3} > 0$ (heat absorbed). D true.

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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