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PhysicsSHMOscillations and SHMMedium2 min

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A particle executes SHM with displacement $y = sin^{2} ω t$ . What are the amplitude and angular frequency of oscillation?

Answer:

Solution:

$sin^{2} ω t = \frac{1}{2} (1 - cos 2 ω t)$ . It oscillates about $y = \frac{1}{2}$ with amplitude $\frac{1}{2}$ and angular frequency $2 ω$ .

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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