Physics - SHM Question with Solution | TestHub

A block of mass $m=\frac{1}{2}\mathrm{kg}$ is attached with two springs each of force constant $k=10{\mathrm{Nm}}^{-1}$ as shown. The block is oscillating vertically up and down with amplitude $A=25\mathrm{cm}$. When the block is at its mean position one of the springs breaks without changing the momentum of the block. (Neglect rotation of the block; take $g=10\mathrm{m}/{\mathrm{s}}^2,\sqrt{3}=1.732$.)

If instead of breaking one spring, the lower half of block of mass $\frac{m}{2}$ would have fallen from the block while it was crossing the mean, then the square of new amplitude is ${\mathrm{xm}}^2$. Calculate 32x.