Two SHMs y 1 = 3 sin ω t and y 2 = 3 sin ω t act along directions 6 0 ∘ apart. Find the amplitude of the resultant SHM.

A = 9 + 9 + 2 ⋅ 9 cos 6 0 ∘ = 27 = 5.20 .

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PhysicsSHMOscillations and SHMMedium2 min

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Two SHMs $y_{1} = 3 sin ω t$ and $y_{2} = 3 sin ω t$ act along directions $6 0^{\circ}$ apart. Find the amplitude of the resultant SHM.

Answer:

5.20

Solution:

$A = 9 + 9 + 2 \cdot 9 cos 6 0^{\circ} = 27 = 5.20$ .

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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