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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediummultiple choice

A spring of spring constant $K$ is fixed to the ceiling of a lift. The other end is attached to a block of mass $m$ , in equilibrium. Now the lift accelerates downwards with acceleration $2 g$ :

Options:(select one or more)

Answer:

B, C

Solution:

In the lift frame $g_{e ff} = g - 2 g = - g$ (upward). New equilibrium: compressed $m g / K$ . The block starts stretched $m g / K$ , so amplitude = $2 m g / K$ and $T = 2 π m / K$ . It passes the natural length, so min P.E. is 0.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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