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PhysicsHeat & ThermoKTGMedium2 minPYQ_2024

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The temperature of an ideal gas is increased from 200 K to 800 K . If r.m.s. speed of gas at 200 K is $v_{0}$ . Then, r.m.s. speed of the gas at 800 K will be:

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Answer:

Solution:

RMS speed, $V_{rms} = \frac{3 RT}{M}$ $\Rightarrow V_{mm} \propto T$ Here, $T_{initiol} = 200 K$ $T_{fing1} = 800 K$ Initial RMS speed $= v_{0}$ $∴ \frac{v _{0}}{v _{rms}} = \frac{200}{800} \Rightarrow v_{ms} = 2 v_{0}$

Stream:BITSATSubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2024

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