10 g of steam at 100°C and 10 g of boiling water at 100°C each fall on skin and cool to 37°C. Using L v = 2260 J / g and c = 4.2 J g − 1 K − 1 , find the ratio of heat released by steam to that by b

Question

10 g of steam at 100°C and 10 g of boiling water at 100°C each fall on skin and cool to 37°C. Using $L_{v} = 2260 J / g$ and $c = 4.2 J g^{- 1} K^{- 1}$ , find the ratio of heat released by steam to that by boiling water. Give the ratio to one decimal place.

Answer:

9.50

Solution:

Water: $10 \times 4.2 \times 63 = 2646 J$ . Steam: $10 \times 2260 + 2646 = 25246 J$ . Ratio $= 25246/2646 = 9.5$ .

TestHub · Accepted Answer

Water: 10 × 4.2 × 63 = 2646 J . Steam: 10 × 2260 + 2646 = 25246 J . Ratio = 25246/2646 = 9.5 .

Physics - Heat & Thermo Question with Solution | TestHub

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