Ice at − 2 0 ∘ C is added to 50 g of water at 4 0 ∘ C , When the temperature of the mixture reaches 0 ∘ C , it is found that 20 g of ice is still unmelted. The amount of ice added to the water was clo

Question

Ice at − 2 0 ∘ C is added to 50 g of water at 4 0 ∘ C , When the temperature of the mixture reaches 0 ∘ C , it is found that 20 g of ice is still unmelted. The amount of ice added to the water was close to (Specific heat of water = 4.2 J / g / ∘ C Specific heat of Ice = 2.1 J / g / ∘ C Heat of fusion of water at 0 ∘ C = 334 J / g )

TestHub · Accepted Answer

Let m gram of ice is added. From principal of calorimeter heat gained (by ice) = heat lost (by water) ∴ 20 × 2.1 × m + ( m − 20 ) × 334 = 50 × 4.2 × 40 376 m = 8400 + 6680 m = 40.1 ​

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