Find the resultant amplitude of X 1 = 2 sin ω t , X 2 = 5 sin ( ω t + 5 3 ∘ ) , X 3 = − 1 sin ω t and X 4 = 0 (take cos 5 3 ∘ = 0.6 , sin 5 3 ∘ = 0.8 ).

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PhysicsSHMOscillations and SHMMedium2 min

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Find the resultant amplitude of $X_{1} = 2 sin ω t$ , $X_{2} = 5 sin (ω t + 5 3^{\circ})$ , $X_{3} = - 1 sin ω t$ and $X_{4} = 0$ (take $cos 5 3^{\circ} = 0.6$ , $sin 5 3^{\circ} = 0.8$ ).

Options:

Answer:

Solution:

Sine part: $2 + 5 (0.6) - 1 = 4$ . Cosine part: $5 (0.8) = 4$ . Amplitude = $16 + 16 = 42$ .

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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