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PhysicsNLMMedium2 minQB

PhysicsMediumsingle choice

The upward normal force exerted by the floor on an elevator passenger who weighs 600 N is 570 N The acceleration of passenger is

Answer:

Solution:

Since, $N < W$ acceleration (a) is downward Also $N = m (g - a)$

$∴ 570 = 60 (g - a) \Rightarrow a = \frac{1}{2} m / s^{2} (↓)]$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

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