A solid cube of mass 5 kg is placed on a rough horizontal surface, in xy-plane as shown. The friction coefficient between the surface and the cube is 0.4 . An external force $F = 6 \hat{i} + 8 \hat{j} + 20 \hat{k}$ is applied on the cube. (use $g = 10 m / s^{2}$ )

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N + 20 − 50 = 0 ⇒ N = 30 f ma x ​ = 0.4 × 30 = 12 6 2 + 8 2 ​ = 10 < 12 ⇒ f = 10 R = 3 0 2 + 1 0 2 ​ = 10 10 ​ A n s = B , C , D ​

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