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PhysicsSHMSuperposition of SHMMedium3 minQB

PhysicsMediumsingle choice

Displacement of a particle is $x = 3 sin 2 t + 4 cos 2 t$ , the amplitude and the maximum velocity will be :-

Answer:

Solution:

Combine: $x = 3 sin 2 t + 4 cos 2 t$ has amplitude $A = 3^{2} + 4^{2} = 5 m$ .

$v_{m a x} = ω A = 2 \times 5 = 10 m / s$

Answer: A

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Superposition of SHM

⏱ 3mℹ️ Source: QB

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