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PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

PhysicsMediumsingle choice

Heat required to melt 1 g ice is 80 cal. A man melts 60 g ice by chewing in one minute. His power is:

Answer:

Solution:

$Q = 60 (80) = 4800 cal$ . Using 1 cal = 4.2 J, $P = \frac{4800 ( 4.2 )}{60} = 336 W$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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