An ideal gas ( γ = 1.40 ) is compressed polytropically from 12 litres to 4 litres, its pressure rising from 1 0 5 Pa to 6 × 1 0 5 Pa. Find the molar heat capacity in this process in units of R (two decimals).

3 n = 6 , so n = ln 3 ln 6 = 1.631 . C = C v + 1 − n R = 2.5 R + − 0.631 R = 0.92 R .

Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesHard2 minQB

PhysicsHardnumerical

An ideal gas ( $γ = 1.40$ ) is compressed polytropically from 12 litres to 4 litres, its pressure rising from $1 0^{5}$ Pa to $6 \times 1 0^{5}$ Pa. Find the molar heat capacity in this process in units of $R$ (two decimals).

Answer:

0.92

Solution:

$3^{n} = 6$ , so $n = \frac{ln 6}{ln 3} = 1.631$ . $C = C_{v} + \frac{R}{1 - n} = 2.5 R + \frac{R}{- 0.631} = 0.92 R$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...