10 g of water at 20°C and 10 g of ice at -30°C are mixed in a container of negligible heat capacity. c w = 4.2 , c ice = 2.1 J / ( g ∘ C ) , L f = 336 J / g . Find the mass of ice present at equilibrium, in g (three decimals).

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PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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10 g of water at 20°C and 10 g of ice at -30°C are mixed in a container of negligible heat capacity. $c_{w} = 4.2, c_{ice} = 2.1 J / (g^{\circ} C), L_{f} = 336 J / g$ . Find the mass of ice present at equilibrium, in g (three decimals).

Answer:

9.38

Solution:

Water cooling to 0°C gives 840 J. Ice warming to 0°C takes 630 J. The spare 210 J melts 0.625 g. Ice left $= 10 - 0.625 = 9.375 g$ ; water $= 10.625 g$ at $0^{\circ} C$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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