A room heated by a heater is at 1 5 ∘ C when the outside is at − 1 5 ∘ C, and at 5 ∘ C when the outside is at − 3 5 ∘ C. Find the temperature of the heater in ∘ C.

k ( T h − 15 ) = c × 30 and k ( T h − 5 ) = c × 40 . Dividing, T h − 5 T h − 15 = 4 3 , so T h = 4 5 ∘ C.

Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferHard2 min

PhysicsHardinteger

A room heated by a heater is at $1 5^{\circ}$ C when the outside is at $- 1 5^{\circ}$ C, and at $5^{\circ}$ C when the outside is at $- 3 5^{\circ}$ C. Find the temperature of the heater in $^{\circ}$ C.

Answer:

Solution:

$k (T_{h} - 15) = c \times 30$ and $k (T_{h} - 5) = c \times 40$ . Dividing, $\frac{T _{h} - 15}{T _{h} - 5} = \frac{3}{4}$ , so $T_{h} = 4 5^{\circ}$ C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

⏱ 2m

Doubts & Discussion

Loading discussions...