A metallic bar heated from 0 ∘ C to 10 0 ∘ C increases in length by 0.05\%. Its linear expansion coefficient is:

α = Δ T ( L Δ L ) . α = 100 ( 100 0.50 ) = 5 × 1 0 − 6 ∘ C − 1 .

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A metallic bar heated from $0^{\circ} C$ to $10 0^{\circ} C$ increases in length by 0.05\%. Its linear expansion coefficient is:

Answer:

Solution:

$α = \frac{( \frac{Δ L}{L} )}{Δ T}$ .

$α = \frac{( \frac{0.50}{100} )}{100} = 5 \times 1 0^{- 6}^{\circ} C^{- 1} .$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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