Two moles of a certain ideal gas at 300 K are cooled at constant volume so that the pressure is reduced to half the original value. Now the gas is heated at constant pressure so that its temperature b

Question

Two moles of a certain ideal gas at 300 K are cooled at constant volume so that the pressure is reduced to half the original value. Now the gas is heated at constant pressure so that its temperature becomes equal to the initial temperature. Find the total amount of heat absorbed by the gas in the process.

TestHub · Accepted Answer

Δ U = 0 over the process, so Q = W . The isochoric step takes T to 150 K, and only the isobaric step does work: W = n R Δ T = 2 × 8.314 × 150 = 2494 J.

Physics - Heat & Thermo Question with Solution | TestHub

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