Find heat in kcal to convert 2 g ice at − 1 0 ∘ C into steam at 11 0 ∘ C . Use c i = c s = 0.5 cal g − 1 ∘ C − 1 , c w = 1 cal g − 1 ∘ C − 1 , L f = 80 cal / g and L v = 540 cal / g .

Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionHard2 minQB

PhysicsHardnumerical

Find heat in kcal to convert 2 g ice at $- 1 0^{\circ} C$ into steam at $11 0^{\circ} C$ . Use $c_{i} = c_{s} = 0.5 cal g^{- 1}^{\circ} C^{- 1}, c_{w} =$ $1 cal g^{- 1}^{\circ} C^{- 1}, L_{f} = 80 cal / g$ and $L_{v} = 540 cal / g$ .

Answer:

1.46

Solution:

Per gram, heat is $0.5 (10) + 80 + 1 (100) + 540 + 0.5 (10)$ . This equals 730 cal/g.

$Q = 2 (730) = 1460 cal = 1.46 kcal .$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...